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X^2-12X+1.14=0
a = 1; b = -12; c = +1.14;
Δ = b2-4ac
Δ = -122-4·1·1.14
Δ = 139.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-\sqrt{139.44}}{2*1}=\frac{12-\sqrt{139.44}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+\sqrt{139.44}}{2*1}=\frac{12+\sqrt{139.44}}{2} $
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